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Use same rank for tied scores

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gsemaj 2023-12-22 22:14:05 -08:00
parent e0e0b3c5e3
commit f02c960497
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1 changed files with 9 additions and 2 deletions
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11
rankendpoint.py
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@ -73,8 +73,15 @@ def get_score_entries(data, name):
# data.append(((999, 'hehe', 'dong', 1))) # data.append(((999, 'hehe', 'dong', 1)))
scores="<{}>\n".format(name) scores="<{}>\n".format(name)
for rank, item in enumerate(data, start=1): rank = 1
scores+='\t<score>PCUID="{}" Score="{}" Rank="{}" FirstName="{}" LastName="{}"</score>\n'.format(item[0], item[3], rank, item[1], item[2]) last_score = -1
for item in data:
score = item[3]
if score == last_score:
rank -= 1
scores+='\t<score>PCUID="{}" Score="{}" Rank="{}" FirstName="{}" LastName="{}"</score>\n'.format(item[0], score, rank, item[1], item[2])
rank += 1
last_score = score
scores+="</{}>\n".format(name) scores+="</{}>\n".format(name)
return scores return scores