CPunch/LuaPytecode
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# LuaPytecode
Parses Lua 5.1 bytecode
# Example
```python
import luac
lc = luac.LuaCompiler()
chunk = lc.compileC("test.lua")
print("\n===== [[Disassembly]] =====\n")
for z in chunk['INSTRUCTIONS']:
i = chunk['INSTRUCTIONS'][z]
if (i['TYPE'] == "ABC"):
print(luac.lua_opcode_names[i['OPCODE']], i['A'], i['B'], i['C'])
elif (i['TYPE'] == "ABx"):
if (i['OPCODE'] == 1 or i['OPCODE'] == 5):
print(luac.lua_opcode_names[i['OPCODE']], i['A'], -i['Bx']-1, chunk['CONSTANTS'][i['Bx']]['DATA'])
else:
print(luac.lua_opcode_names[i['OPCODE']], i['A'], -i['Bx']-1)
```
or just parse lua bytecode
```python
bytecode = "27\\76\\117\\97\\81\\0\\1\\4\\8\\4\\8\\0\\21\\0\\0\\0\\0\\0\\0\\0\\112\\114\\105\\110\\116\\40\\39\\104\\101\\108\\108\\111\\32\\119\\111\\114\\108\\100\\39\\41\\0\\0\\0\\0\\0\\0\\0\\0\\0\\0\\0\\2\\2\\4\\0\\0\\0\\5\\0\\0\\0\\65\\64\\0\\0\\28\\64\\0\\1\\30\\0\\128\\0\\2\\0\\0\\0\\4\\6\\0\\0\\0\\0\\0\\0\\0\\112\\114\\105\\110\\116\\0\\4\\12\\0\\0\\0\\0\\0\\0\\0\\104\\101\\108\\108\\111\\32\\119\\111\\114\\108\\100\\0\\0\\0\\0\\0\\4\\0\\0\\0\\1\\0\\0\\0\\1\\0\\0\\0\\1\\0\\0\\0\\1\\0\\0\\0\\0\\0\\0\\0\\0\\0\\0\\0".split('\\')
bytecode = list(map(int, bytecode))
lc = luac.LuaCompiler()
chunk = lc.decode_bytecode(bytecode)
```